MINI Hall effect sensor conversion?

[russyj]

position 1 = rest (voltage feed)
position 2 = switching (no volts)
position 3 = fire (voltage feed)
Now if that is the case and i'm not just being a complete numpty, the surely there must be room in there somewhere for a microswitch, and if this is the case surely a 2 way switch would supply the correct path for voltage feeds?

if this is the case, then the board senses the lack of current at the engagment of the trigger pull, and the re-connection of the current as the firing process. Thus, taking 1 as current flowing, and 0 as current not flowing, one full cycle of the trigger from the trigger being untouched, engaged then released again, should be:
10101
A microswitch works by engaging current when depressed, much like a reed swith or standard breaker switch in gcse electronics, thus one trigger pull would be:
010

So by putting a microswitch on without reprogramming the board, surely it would only fire every 2 trigger pulls? Course, this would eliminate a lot of bounce...

If any of that is stupid, I am VERY tired...

 

[Lucky]

Its just asking for trouble isnt it.
Form an orderly queue after this line.
________________________________

I know you'd tell me that, but i like to hear it from others occasionally.

It makes me feel special.........."special needs"

 

[Lucky]

if this is the case, then the board senses the lack of current at the engagment of the trigger pull, and the re-connection of the current as the firing process. Thus, taking 1 as current flowing, and 0 as current not flowing, one full cycle of the trigger from the trigger being untouched, engaged then released again, should be:
10101
A microswitch works by engaging current when depressed, much like a reed swith or standard breaker switch in gcse electronics, thus one trigger pull would be:
010

So by putting a microswitch on without reprogramming the board, surely it would only fire every 2 trigger pulls? Course, this would eliminate a lot of bounce...

If any of that is stupid, I am VERY tired...

Possibly?"
Or is it
1-that at rest the "hall" feeds voltage to wire "A" on the board and the board knows that feed means that the trigger is at rest.
2-then it swings over a dead mans area suppling no voltage anywhere.
3-it supply's voltage to wire "B", telling the board to fire
2-then it swings over a dead mans area suppling no voltage anywhere.
1-that at rest the "hall" feeds voltage to wire "A" on the board and the board knows that feed means that the trigger is at rest.
Only reason i say it like that is because that is the type of switching system utilised on certain forklifts that i work on, to tell the logic board that the driver has put his foot on the throttle and now systems need to start doing things, and when they go wrong....yep we cut them out and wire in a big microswitch.
It's probably different on a marker, but it's worth a thought, but then i've blown forklifts up before by thinking i knew what i was doing

 

[russyj]

Possibly?"
Or is it
1-that at rest the "hall" feeds voltage to wire "A" on the board and the board knows that feed means that the trigger is at rest.
2-then it swings over a dead mans area suppling no voltage anywhere.
3-it supply's voltage to wire "B", telling the board to fire
2-then it swings over a dead mans area suppling no voltage anywhere.
1-that at rest the "hall" feeds voltage to wire "A" on the board and the board knows that feed means that the trigger is at rest.
yep we cut them out and wire in a big microswitch.

Thats what I initially thought, with feeds A and B, however I cannot see the point of this in the paintblal and forklift applications. Certain applications need the three states, but for most stuff, surely two states are all that are needed? The only possible advantage I can see is an extra millisencond or two of prep time between the trigger being at rest, and the gun about to fire, i.e.
A - at rest
0 - about to fire - prepare solenoid? *will come back to this
B - firing cycle

My problem with this would be that you could short stroke the trigger, dependant on what part 0 would do. I.e. what happens if you send the signal to the board of A0A0A0B?

* One possibility is if the mini has some weird reg setup (I know next to nothing about minis) where there is an electronic actuation needed somewhere other than the solenoid (say, an electronic reg? guessin here) it would need the 0 state to perhaps prep this. This is still somewhat illogical though, because regulators are constantly ready as soon as they are full, and they would not be able to refil in the time between the trigger hitting 0 and B

IF the A 0 B theory is correct, whacking in a microswitch would cause some problems, as you would be left with a 0 B opperation, meaning whenever the trigger was at rest the gun would be doing whatever its meant to be doing at 0, which clearly should not take long as it was origionally meant to happen in a mater of milliseconds. Having this stage of the operation constantly on might cause probems, especially for battery life.

yep we cut them out and wire in a big microswitch.

Lol, at what point does it stop becoming a microswitch, and just start being a switch?

 

[SWAT-Jay-]

The hall effect sensor provides a voltage output which is proportional to the magnetic field strength at its surface, the closer the magnet to its surface the more voltage it will produce as an output.
This means that there is probably some sort of comparator on the board which tells it to fire when the signal voltage reaches a certain level. By using a Microswitch this is like removing the proporionality of the sensor and just having an on/off so the comparator will be useless but still there and no need to remove it.
I think its possible to do but does the mini have enough space avaliable for you to do this? can you find a microswitch with the same physical size as the hall effect sensor? and wont you have to drill your gat?

 

[Lucky]

Thats what I initially thought, with feeds A and B, however I cannot see the point of this in the paintball and forklift applications.

A - at rest
0 - about to fire - prepare solenoid? *will come back to this
B - firing cycle

My problem with this would be that you could short stroke the trigger, dependant on what part 0 would do. I.e. what happens if you send the signal to the board of A0A0A0B?

It's a long day and i'm tired but i'm missing why "0 - about to fire - prepare solenoid?"

On our systems there is no "O" it is purely just a transition phase between A and B, like the dead spot on a microswitch which is neither open or closed, it doesn't supply to anywhere and thus i question how exactly you prepare a solenoid? I realise you have a problem with that too but i don't just see it as a plausible working system

IF the A 0 B theory is correct, whacking in a microswitch would cause some problems, as you would be left with a 0 B opperation, meaning whenever the trigger was at rest the gun would be doing whatever its meant to be doing at 0, which clearly should not take long as it was origionally meant to happen in a mater of milliseconds. Having this stage of the operation constantly on might cause probems, especially for battery life.

Fitting a microswitch would give you A-B and not O-B, So a missed trigger operation would infact not matter as a sequence of ABAAAAAB would only fire the gun twice.
On our trucks, the A is required to effectively restart the drive sequence, remove the A feed and the truck goes nowhere. On a marker this A could be used to cycle the gun after it has fired so that it is ready for the next B-ang, all of which happens in a nano-second.

Lol, at what point does it stop becoming a microswitch, and just start being a switch?

Simple! When it's bigger than a Micro........how big's a Micro? Now there's a debate