Originally posted by Thordic
Using this formula:
Air has an average molecular weight of 29 (28 for N2*.8 + 32 for O2 * .2)
1 mole of gas at STP occupies a volume of 22.4 L, therefore, 29g {~1 oz)of air at STP occupies 22.4 L
Take you tank volume in Liters (ft3X28.3 or cu in X .0164) and correct to STP (forget the temperature, just multiply the volume by 204 or 306{3000psi/14.7psi; 4500/14.7psi}. This gives you the gas volume at STP.
Divide this volume by 22.4 and you get the weight of air in oz.
Using that, you get the following information:
3000 PSI = 204 atm
4500 PSI = 306 atm
47ci = 0.77 L
68ci = 1.11 L
88ci = 1.44 L
114ci = 1.87 L
So now, just plug it into what I said above, and you get these weights:
47ci 3000PSI tank: 7.0 ounces of air
68ci 3000PSI tank: 10.1 ounces of air
88ci 3000PSI tank: 13.1 ounces of air
114ci 3000PSI tank: 17.0 ounces of air
47ci 4500PSI tank: 10.5 ounces of air
68ci 4500PSI tank: 15.1 ounces of air
88ci 4500PSI tank: 19.7 ounces of air
114ci 4500PSI tank: 25.5 ounces of air
As you can see, the weight of compressed air is not negligible, especially in higher pressure setups.