Maths Quiz.

[xDansomee]

As you put it that way you can fit 551 Ball bearings (551.782 if you want the cut one up)

Working:
Ball bearing Radius= 1.25mm
volume= (4/3)(pi)(radius)cubed
1 ball bearing volume= 8.181230869mm
1 meter/0.008.181230869 meter= 551.782

Been so long since i've done maths...... though I feel i've gone wrong.

The above calculations are correct, just not for this

Although, that answer seems too small, although I could be wrong

If lined up side by side, there would be 4 bearings per 1 cm, so in an area of 1cm2 there would be 16 bearings.

So, side by side at the bottom of the box, there would be 1600 bearings...

Is the answer to question 1; 320,000? Or close to that.

EDIT: Oops, why did I times it by 200?

1600 x 40, so 64,000?

--

So for surface area; 4(pi)r2... 4 x Pi x 1.25mm2.

= 19.63495408mm.

Above x 64,000 = 1256637.061mm <- Surface area.

--

All of that is probably wrong, and i've just wasted 10 mins

 

[FrontlineArtist]

If lined up side by side, there would be 4 bearings per 1 cm, so in an area of 1cm2 there would be 16 bearings.

So, side by side at the bottom of the box, there would be 1600 bearings...

Ah right I see I was playing with the volume, I was going wrong way around it.

So Cook$ was right.

 

[Bon]

Nobody is right yet When the right answer is posted I will let you know

 

[xDansomee]

Nobody is right yet When the right answer is posted I will let you know

I thought you meant cooks was for the first part?

1,120,000?

I'm trying to do the little calculations in my head.

The way they would stack, if they were in 'neatly' would be approx 7 layers of bearings per 1cm of height gained.

 

[FrontlineArtist]

I've just realised were all forgetting the gaps beween the balls so far were thinking the balls stack like this:
#####
#####
#####

Where they can be stacked like so:
#####
# # #
#####

effectively adding another layer of balls in the box

 

[Cook$]

Yeah, I thought of that too, but couldn't be bothered tryin to work that out so just went the easy way.

 

[xDansomee]

Yeah, I was taking that into account... But just realised i'd forgotten some 0's on my numbers

If this number ain't right, meh

318,404.

If above is right, surface area = 6,251,847mm

 

[gaunt]

1) 116,827,966 ball bearings

2) Total surface area 9,175,646 meters

edit: Sorry if I ruined everyone's fun. If its right that is.

 

[xDansomee]

1) 116,827,966 ball bearings

2) Total surface area 9,175,646 meters

edit: Sorry if I ruined everyone's fun. If its right that is.

Oops, can't read.

Nealy 117 million? Thats a tad high And I doubt 9 million meters of surface area aswell mate.

 

[FrontlineArtist]

1) 116,827,966 ball bearings

2) Total surface area 9,175,646 meters

edit: Sorry if I ruined everyone's fun. If its right that is.

Argh really? I just ordered a 1x1x1 box of ball bearings, had to pay more for the special request:tsk: